Question 924035
p(Canadian license plates)= 0.12
p(camper)= 0.28
p( camper with Canadian license plates)= 0.09
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(a) P(camper with Canadian license plates) = .12
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 (b) P(a vehicle with Canadian license plates  is a camper) 
P(A|B) = P(A and B)/P(B)
P(Camper| Canadian Plates) = .09/.12 = .75
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 (c) P( vehicle  A:does not have Canadian plates 0r B: is not a camper) 
P(A 0r B) = P(A) + P(B) - P(A and B) = .88 + .72 - .81 = .80