Question 924038
p(walks) = 1/2  , p(Arriving Late) =  1/6
p(cycles) = 1/3 , p(Arriving Late) =  1/4
p(takes the bus)= 1/6 , p(Arriving Late) =  1/5
A)  P(arrives late) = {{{ (1/2)(1/6) + (1/3)(1/4) + (1/6)(1/5) }}}= 12/60 = 1/5
....
B) 60(1/5) = 12 occassions of being Late would be expected.