Question 923954
{{{log((6x-21))=2+log((x-9))}}}



{{{log((6x-21))-log((x-9))=2}}}



{{{log(((6x-21)/(x-9)))=2}}} Use log rule #2 from <a href="http://www.purplemath.com/modules/logrules.htm">this page</a>



{{{(6x-21)/(x-9)=10^2}}}



{{{(6x-21)/(x-9)=100}}} Convert to exponential form (logs without stated bases are by default in base 10)



{{{6x-21=100(x-9)}}}



{{{6x-21=100x-900}}}



{{{6x-21+900=100x}}}



{{{-21+900=100x-6x}}}



{{{879=94x}}}



{{{94x=879}}}



{{{x=879/94}}}


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Answer:


The exact answer is {{{x=879/94}}}


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