Question 923954
Use algebraic procedures to find the exact solution(s) of the equation. 
log(6x-21)=2+log(x-9)
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You need to know:: log(A)-log(B) = log(A/B)
and
logx(3) 2 implies that 3 = x^2
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Your problem::
log(6x-21) - log(x-3) = 2
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log[(6x-21)/(x-3)] = 2
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(6x-21)/(x-3) = 10^2
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6x-21 = 100x - 300
94x = 279
x = 2.9681
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Cheers,
Stan H.
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