<PRE><B>Question 923722</B>
Solve the following triangle for the remaining angles and sides. This triangle has 2 cases:
 side a = 3 
angle A = 10 degrees 
side b = 4
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Law of Sines::
sin(B)/4 = sin(10)/3
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sin(B) = (4/3)sin(10) = 0.2315
B = arcsin(0.2315) = 13.39 degrees or B = 180-13.39 = 166.61 degrees
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C = 180-(10 + 13.39) = 156.61 degrees OR C = 3.39 degrees
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If C = 156.61 degrees,
c/sin(156.61) = 4/sin(10)
C = 0.3970*4/0.1736 = 9.145
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If C = 3.39 degrees
C/sin(3.39) = 4/sin(10)
C = 1.36 
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Cheers,
Stan H.
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