Question 923749
given:

{{{A=6sqrt(2)cm^2=6*1.41cm^2}}}=>{{{A=8.46cm^2}}}
the length of one leg is {{{a=sqrt(12)cm}}}=>{{{highlight(a=3.464cm)}}}

{{{A=a*b/2}}} where base {{{a=one_leg}}} and height {{{b=other_leg}}}

{{{8.46cm^2=(3.464cm*b)/2}}}

{{{2*8.46cm^2=3.464cm*b}}}

{{{16.92cm^2=3.464cm*b}}}


{{{16.92cm^2/3.464cm=b}}}

{{{b=4.884526558891455cm}}}

{{{highlight(b=4.89cm))}}}-the length of the other leg

What is the length of the hypotenuse {{{c}}}?

{{{c^2=a^2+b^2}}}

{{{c^2=(3.464cm)^2+(4.89cm)^2}}}

{{{c^2=11.999296cm2+23.9121cm^2}}}

{{{c^2=35.911cm^2}}}

{{{c=sqrt(35.9cm^2)}}}

{{{c=5.99166cm}}}

{{{highlight(c=5.99cm)}}}