<PRE><B>Question 923834</B>
the standard slope-intercept form for an equation of a line is 
{{{y = highlight_green(m)x + highlight(b)}}}  where m is the slope and b the y-intercept.  
3x - y = -3   
0r   y = 3x+3
Line parallel to the line y = 3x+3 and passing through the point (4, -2).
***Using point-slope form, {{{y - y[1] = m(x - x[1])}}}
y + 2 = 3(x-4)
y = 3x -14
0r....In Standard Form
3x - y = 14

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