<PRE><B>Question 923831</B>
The area of a triangular flag is 132 sq. centimeters. Its altitude is 2 centimeters longer than twice its base. Find the lengths of the altitude and the base. 
---
Area = length*width
----
L = x
W = 2x+2
------------------
132 = x*(2x+2)
2x^2 + 2x - 132 = 0
x^2 + x - 66 = 0
---
x = [-1 +- sqrt(1 -4*-66)]/2
---
x = [-1 +- sqrt(265)]/2
---
x = 7.64 cm
2x+2 = 17.68 cm 
-------------
Cheers,
Stan H.
-------------


</PRE>