Question 78127
For each of these problems it's easiest to use the quadratic formula (since there are going to be complex roots):

{{{w^2=-225}}}

{{{w^2+225=0}}} Add 225 to both sides

Now lets use the quadratic formula:

*[invoke quadratic "w", 1, 0, 225 ]


So we have 2 complex (or imaginary) solutions:

{{{x=15i}}} or {{{x=-15i}}}

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Again lets use the quadratic formula:

*[invoke quadratic "v", 3, 4, -1 ]

So we have 2 real solutions:

{{{x=-1.54858377035486}}} or {{{x=0.21525043702153}}}