Question 923777
f(x) crosses the x-axis at x = 3. f is positive on [-1, 3) and negative on (3, 6].


*[tex \large Area = \int_{-1}^3 9 - x^2 \, dx - \int_3^6 9 - x^2 \, dx]


*[tex \large = (9x - \frac{x^3}{3}) \, |_{-1}^3 - (9x-\frac{x^3}{3}) \, |_{3}^6]


And you can simplify the rest.