Question 923678
mean = 420 grams. Assume the standard deviation of the weights is 21 grams
 sample of 45 loaves is to be randomly selected. 
(b) Find the mean of this sampling distribution. (Give your answer correct to nearest whole number.) 420gm

 (c) Find the standard error of this sampling distribution. (Give your answer correct to two decimal places.) 
{{{21/sqrt(45)}}} = 3.13

 (d) What is the probability that this sample mean will be between 416 and 424? (Give your answer correct to four decimal places.) 
z = -4/3.13 = -.278   and z = 4/313 = .278
P(416 < x < 424)= normalcdf(-.278, .278) = .6068

 (e) What is the probability that the sample mean will have a value less than 410? (Give your answer correct to four decimal places.) 
P(x-bar < 410) =P(z < -10/3.13)= .0007

 (f) What is the probability that the sample mean will be within 3 grams of the mean? (Give your answer correct to four decimal decimal places.) 
P (417 x < 423) = normalcdf( -3/3.13, 3/3.13)= .6622