Question 923675


{{{log(x^2-15)=1}}} ...you have log base {{{10}}}, then we can write {{{1}}} as {{{log(10)}}} because {{{log(10,10)=1}}}


{{{log(x^2-15)=log(10)}}} ...if log same, then {{{x^2-15=10}}} is same too

{{{x^2-15=10}}}...solve for {{{x}}}

{{{x^2=10+15}}}

{{{x^2=25}}}

{{{x=sqrt(25)}}}

so, {{{x=5}}} or {{{x=-5}}}