Question 923481
Using common logs and A(2.7)=1/2 and A(0)=1,


{{{highlight_green(1/2=1*a^(2.7))}}}


{{{log((1/2))=log((a^(2.7)))}}}


{{{log((1/2))=2.7*log((a))}}}


{{{log((a))=log((1/2))/2.7}}}


{{{log((a))=-(0.30103)/(2.7)}}}  


{{{highlight_green(log((a))=-0.11149)}}}


{{{highlight(a=0.773584)}}} based on {{{10^(-0.111493)}}}.