Question 923511
No poundage quantities of the coffees A and B nor the mixture is given.  


{{{(4.40u+5.95v)/(u+v)=p}}}, p is price for the mixture, but you also KNOW THE COST of the mixture...
{{{(4.4u+5.95v)=421.30}}}


You also are given a ratio of type B to type A.
{{{v/u=3}}}


Type A is the more expensive coffee, assigned quantity of pounds v.
{{{u/v=1/3}}}
{{{u=v/3}}}
-
{{{(4.4*v/3+5.95v)=421.30}}}
{{{4.4v+3(5.95)v=3(421.30)}}}
{{{(4.4+3*5.95)v=3(421.30)}}}
{{{highlight(v=(3*421.30)/(4.4+3*5.95))}}}



To the nearest whole value, that is 58 pounds of type A coffee.