Question 923465
A horse and a chicken are are standing at a point on a 1/4 mile track.
 The horse heads in one direction at 26mph while the chicken heads in the opposite direction at 4mph.
 How many seconds will pass before they meet again
:
Convert their speeds to feet/sec
{{{(26*5280)/3600}}} = 38.13 ft/sec for the horse
{{{(4*5280)/3600}}} = 5.87 ft/sec
Convert 1/4 mi to {{{5280/4}}} = 1320 ft
When the horse meets the chicken they will have traveled a total 1320 ft
let t = no. of seconds for this to happen
38.13t + 5.87t = 1320
44t = 1320
t = 1320/44
t = 30 seconds
:
much easier way to do it, since they are going towards each other the relative speed is 26 + 4 = 30 mph
How long to go 1/4 mi at 30 mph: Use .25 for 1/4, convert to seconds
{{{.25/30}}} * 3600 = 30 sec