Question 923134
how many liters of a 20% solution must be mixed with 40 Liters of an 80% solution, in order to get a mixture that is 40% acid?
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let x=amt of 20% solution to mix
20%x+80%*40=40%(x+40)
.20x+32=.40x+16
.20x=16
x=80
amt of 20% solution to mix=80 liters