Question 922936
how many oz of water do i add to 32 oz of 40% acid solution if i want a 20% solution.
:
let w = amt of water required to accomplish this
the amt of acid remains the same, only the per cent changes, therefore
.40(32) = .20(w+32)
12.8 = .2w + 6.4
12.8 - 6.4 = .2w
6.4 - .2w
w = 6.4/.2
w = 32 oz of water to be added.