Question 77926
logarithms are essentially exponents


so (when the base is the same) the log of the product (multiplying) of numbers is the sum of their logs, and the log of the quotient (dividing) of two numbers is the difference of their logs


5*13=65 so log(65)=log(5)+log(13) regardless of base...similarly log(13/5)=log(13)-log(5)


since logb(5)=.8271 and logb(13)=1.3181...logb(65)=2.1452 and logb(13/5)=0.491...(incidentally b=7)