Question 78064
{{{x^2 - 8x + 16=-10 +16}}}

{{{x^2 - 8x + 16=6}}} Combine like terms

{{{(x-4)^2=6}}} Since the left side is a perfect square it becomes {{{(x-4)^2}}}

If you want to solve for x then you simply take the square root of both sides

{{{x-4=0+-sqrt(6)}}}

{{{x=0+-sqrt(6)+4}}} Add 4 to both sides

So our answer is:

{{{x=sqrt(6)+4}}} or {{{x=-sqrt(6)+4}}}