Question 78066
The sum of two numbers is twenty five and the sum of their square is three hundred and twenty five. Find the numbers.
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Let one of the numbers be "x"; the other must be "25-x".
EQUATION:
x^2+(25-x)^2=325
x^2+625-50x+x^2=325
2x^2-50x+300=0
x^2-25x+150=0
x=[25+-sqrt(625-4*150)]/2
x=[25+-5]/2
x=15or x=10
One of the numbers is 15; the other is 10

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Cheers,
Stan H.