Question 922571
Please explain to me step by step how to come to the final answer for the following equation:
What you wrote is not an equation, lets assume you mean
{{{2x^4-128=0}}}
divide through by 2, and you have
{{{x^4 - 64 = 0}}}
Factors to
{{{(x^2-8)(x^2+8)= 0}}}
the real solutions
{{{x^2 = 8}}}
{{{x = +sqrt(8)}}} = {{{2*sqrt(2)}}}
and
{{{x = -sqrt(8)}}} = {{{-2*sqrt(2)}}}