Question 922480
log6(5x^3)+log6(4x) = log6(20x^4)
..........
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]****
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]