Question 922474
<pre>
{{{(1-i)/(-9+2i)}}}

The conjugate of the denominator -9+2i is formed by changing 
the sign of only the imaginary part, getting -9-2i.

So we multiply by {{{(-9-2i)/(-9-2i)}}} which just equals 1.

{{{(1-i)/(-9+2i)}}}{{{"×"}}}{{{(-9-2i)/(-9-2i)}}}

{{{((1-i)(-9-2i))/((-9+2i)(-9-2i))}}} 

Use FOIL on numerator and denominator:

{{{(-9-2i+9i+2i^2)/(81+18i-18i-4i^2)}}}

{{{(-9+7i+2i^2)/(81-4i^2)}}}

Replace i² by -1

{{{(-9+7i+2(-1))/(81-4(-1))}}}

{{{(-9+7i-2)/(81+4)}}}

{{{(-11+7i)/85}}}

{{{-11/85+(7i)/85}}}

{{{-11/85+expr(7/85)i}}}

Edwin</pre>