Question 922349

The diagonal of a rectangle has a length 50. If its legs are in the ratio 3:4 , what is its perimeter? Thank you!
<pre>
Let the multiplicative factor be x
Then the shorter leg measures 3x, and the longer leg measures 4x
Using the pythagorean formula, we get: 
{{{(3x)^2 + (4x)^2 = 50^2}}}
{{{9x^2 + 16x^2 = 2500}}}
{{{25x^2 = 2500}}}
{{{25(x^2) = 25(100)}}}
{{{x^2 = 100}}}
x, or multiplicative factor = {{{sqrt(100)}}}, or 10

Measure of shorter leg: 3(10), or 30 units
Measure of longer leg:  4(10), or 40 units
Perimeter of rectangle: 2(30 + 40), or 2(70), or {{{highlight_green(140)}}} units