Question 922386


{{{4^x/2^(-1)=8^(2-x)}}}

{{{4^x/(1/2)=8^2/8^x}}}

{{{4^x*2=64/8^x}}}

{{{4^x*2*8^x=64}}}

{{{4^x*8^x=64/2}}}

{{{32^x=32}}} 

{{{32^x=32^1}}} ...since bases same, exponents are same too: => {{{x=1}}}