<PRE><B>Question 922293</B>
The peak of Mt. Everest is approximately 12,400 feet high. A trigonometry student, several miles away, notes that the angle between level ground and the peak is 35°. Estimate the distance from the student to the point on level ground directly beneath the peak. 
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Draw the picture::
You have a right triangle with base angle = 35 degrees
and side opposite = 12,400
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Equation to find the base distance::
tan(35) = 12400/b
b = 12400/tan(35) = 17,709 ft
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Cheers,
Stan H.
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