Question 922376
The event of x and y are mutually exclusive. Suppose p(x) .05 and p(y) is .02. What is the probability that neither x nor y will happen
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P(x Or y) = 0.05 + 0.02  = 0.07
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Then P(x Or y)' = 1 - 0.07 = 0.93
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Cheers,
Stan H.
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