Question 922148
The amount of snowfall falling in a certain mountain range is normally distributed with a mean of 74 inches, and a standard deviation of 12 inches. what is the probability that the mean annual snowfall during 36 randomly picked years will exceed 76.8 inches? (I know the answer I do not know how to get the answer)
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t(76.8) = (76.8-74)/(12/sqrt(36)) = 2.8/(2) = 1.4
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P(x-bar > 76.8) = P(t > 1.4 when df = 35) = tcdf(1.4,100,35) = 0.3458
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Cheers,
Stan H.
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