Question 922090
{{{cot (t) = -0.8=-4/5 = adj/opp}}}

The hypotenuse is {{{sqrt(4^2 + 5^2) = sqrt(41)}}}

{{{sin (t) = -5/sqrt(41)}}} ...{{{Sine = opp/hyp}}}, negative in quadrant IV
{{{cos (t) = 4/sqrt(41).......{{{ Cosine = adj/hyp}}}


{{{sin(t + 4pi) = sin (t) = -5/sqrt(41)}}}. The period of sine is {{{2pi}}}
{{{tan(t + 11pi) = tan( t)=sin(t)/cos(t)=(-5/sqrt(41))/(4/sqrt(41)) = -5/4}}}. The period of tan is {{{pi}}}