Question 922006


if you are driving a car at {{{15(mil/h)}}}, means the speed is {{{s=15(mil/h)}}}

and the distance you have to travel is {{{3mil}}}, means the distance {{{d=3mil}}} 


how long will it take you, means what is a time {{{t}}}

as you know, the distance is directly proportional to speed and time: 
as speed goes up, travel distance goes up
as time goes up, travel distance goes up

therefore, {{{d=s*t}}}

but
speed and travel time are Inversely Proportional because the faster we go the shorter the time

    as speed goes up, travel time goes down
    and as speed goes down, travel time goes up


therefore, {{{t=d/s}}}

so, since you need to calculate the time, use this formula 

{{{t=d/s}}} ....plug in given data {{{d=3mil}}} and {{{s=15(mil/h)}}}


{{{t=3mil/15(mil/h)}}} ...simplify


{{{t=cross(3)1cross(mil)/cross(15)5(cross(mil)/h)}}}


{{{t=1/5(1/h)}}}


{{{t=(1/5)h}}}


{{{t=0.2h}}}....convert it to min, multiply by {{{60}}}


{{{t=0.2*60min}}}


{{{t=12min}}} => it will take you {{{12min}}} to travel the distance of {{{3mil}}} and speed of {{{15(mil/h)}}}