Question 921925
We are given,
M = 0.67*log(0.36E) + 1.46
suppose we have a magnitude 6.0 earthquake, then we ask how many kilowatt hours(E) are released?
6.0 = 0.67*log(0.36E) + 1.46 
0.67*log(0.36E) = 6.0 - 1.46 = 4.54
log(0.36E) = 4.54 / 0.67 = 6.776119403
now use product of logarithms rule
log(0.36) + log(E) = 6.776119403
 -4.4369749923e-1 + log(E) = 6.776119403
log(E) = 6.776119403 + 4.4369749923e-1 = 7.219816902
now use definition of logarithm
E = 10^7.219816902 = 16588873.760056074
E = 1.6588874e7 kilowatt hours were released