<PRE><B>Question 921966</B>
let woman age be x now. Her son&#39;s age be y now
 woman is six times as old as her son.
            x =6*y
             x =6y
In 9 years she will be three times as old as her son
            so, after  9 years her age will be x+9 &amp; her son&#39;s age will be y+9
so,  x+9 = 3*(y+9)
   put x=6y in the above equation
       6y+9= =3*(y+9)
         6y+9= 3y+ 3*9
         6y+9 = 3y+27
        subtract 3y on both sides
      6y+9 -3y= 3y+27-3y
        3y+9= 27
          subtract 9 on both sides
           3y+9-9=27-9
          3y= 18 
 divide with 3 on both sides
       3y/3  = 18/3
          y= 6
       so age of son now (y) = 6
       age of woman (x=6y)  = 6*6 =36
age of son is 6 years and woman is 36 years
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