Question 921791
a parallelogram is quadrilateral with both pairs of opposite sides parallel

let' graph them and see: 

just find two points for each and draw a line through:

{{{y=4x+5}}}, find intercepts

if {{{x=0}}}=> {{{y=4*0+5}}}=> {{{y=5}}}=> y-intercept is at ({{{0}}},{{{5}}})

if {{{y=0}}}=> {{{0=4x+5}}}=> {{{x=-5/4}}}=> x-intercept is at ({{{-5/4}}},{{{0}}})


{{{y=(1/3)x+7}}}

if {{{x=0}}}=> {{{y=(1/3)0+7}}}=> {{{y=7}}}=> y-intercept is at ({{{0}}},{{{7}}})

if {{{y=0}}}=> {{{0=(1/3)x+7}}}=> {{{x=-7/(1/3)=-21}}}=> x-intercept is at ({{{-21}}},{{{0}}})

{{{8x-2y=1}}}

if {{{x=0}}}=> {{{8*0-2y=1}}}=> {{{y=-1/2}}}=> y-intercept is at ({{{0}}},{{{-1/2}}})

if {{{y=0}}}=> {{{8x-2*0=1}}}=> {{{x=1/8}}}=> x-intercept is at ({{{1/8}}},{{{0}}})

and {{{x-3y=2}}}


if {{{x=0}}}=> {{{0-3y=2}}}=> {{{y=-2/3}}}=> y-intercept is at ({{{0}}},{{{-2/3}}})

if {{{y=0}}}=> {{{x-3*0=2}}}=> {{{x=2}}}=> x-intercept is at ({{{2}}},{{{0}}})



{{{ graph( 600, 600, -10, 10, -10, 10, 4x+5, (1/3)x+7,-x/3+2/3,4x-1/2) }}}


both pairs of opposite sides are {{{not}}} parallel; so, it's not a parallelogram