<PRE><B>Question 78028</B>
Let x=first integer
Three times the first integer=3x

Then x+1=the second integer
Seven times the second integer=7(x+1)

Now we are told that if we add three times the first and seven times the second we end up with 47, so:

3x+7(x+1)=47  get rid of parens

3x+7x+7=47  subtract 7 from both sides

3x+7x+7-7=47-7  collect like terms

10x=40  divide both sides by 10

x=4-------------------------------------first integer

4+1=5--------------------------------------second integer

CK

3*4+7*5=47
12+35=47
47=47


Hope this helps----ptaylor</PRE>