Question 921744

let numbers be {{{x}}} and {{{y}}};

if  number {{{x}}} is five times number {{{y}}},then

{{{x=5y}}}......eq.1

 and if the {{{x+y=36}}}........eq.2, then we have to solve system

{{{x=5y}}}......eq.1
{{{x+y=36}}}........eq.2
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{{{x+y=36}}}........eq.2..substitute {{{x}}} from eq.1

{{{5y+y=36}}}

{{{6y=36}}}

{{{y=36/6}}}

{{{y=6}}}

now, back to eq.1 and find {{{x}}}

{{{x=5y}}}......eq.1

{{{x=5*6}}}

{{{x=30}}}

so, your numbers are: {{{6}}} and {{{30}}}