Question 921678
xyz is a right angled triangle at y if 
2yz = 4xy find 

1-sinēx - cosēz

2sin(x)cos(z) - tan(z)

<pre>
2yz = 4xy

Divide both sides by 2y

z = 2x

x and z are complementary because they are
the two acute angles of a right triangle.

So z+x = 90° and z = 90°-x

90°-x = 2x
  90° = 3x
  30° = x

And since z = 2x

z = 2(30°) = 60°

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1 - sinēx - cosēz
1 - sinē(30°) - cosē(60°)
1 - {{{(1/2)^2}}} - {{{(1/2)^2}}}
1 - {{{1/4}}} - {{{1/4}}}
1 - {{{1/2}}}
{{{1/2}}}

---

2sin(x)cos(z) - tan(z)

2sin(30°)cos(60°) - tan(60°)

{{{2(1/2)(1/2) - sqrt(3)}}}

{{{1/2 - sqrt(3)}}}

{{{(1-2sqrt(3))/2}}}

Edwin</pre>