Question 78006
If you want to factor these then:

Lets factor {{{x^2-5x+4}}}

*[invoke factoring_quadratics 1, -5, 4]




Now lets factor {{{a^4+a^3+a^2}}} 


{{{a^2(a^2+a+1)}}} Factor out {{{a^2}}} This is the simplified form




Now lets factor {{{3b^2+b+4}}} (we're going to use x instead of b)


*[invoke factoring_quadratics 3, 1, 4]


So this means we cannot factor {{{3b^2+b+4}}}