Question 921580
recall equation of a circle in standard form:
 
{{{(x-h)^2 + (y-k)^2 = r^2}}}

where {{{r}}} is the radius of the circle, and ({{{h}}},{{{k}}}) are the coordinates of its center

{{{(x+1)^2 + (y+6)^2 = 16}}} ..so, here you have a circle with center at ({{{-1}}},{{{-6}}} and radius {{{r=4}}}

{{{ drawing( 600, 600, -10, 10, -15, 10, circle(-1,-6,0.12),locate(-1.5,-6,C(-1,-6)), circle(-1,-6,4),graph( 600, 600, -10, 10, -15, 10) ) }}}