Question 921556

{{{x^2-2x-35=0}}} ...factor completely, write {{{-2x}}} as {{{+5x-7x}}}


{{{x^2+5x-7x-35= 0}}}...group


{{{(x^2+5x)-(7x+35)= 0}}}


{{{x(x+5)-7(x+5)= 0}}}


{{{(x-7)(x+5)= 0}}}

solutions:

if {{{(x-7)= 0}}}, then {{{x= 7}}}

if {{{(x+5)= 0}}}, then {{{x=-5}}}



{{{ graph( 600, 600, -10, 10, -50, 10, x^2+5x-7x-35) }}}