Question 921522
 find the {{{x}}} and {{{y}}} intercepts for the graph of 

{{{y=log(10-3x)}}}

 the {{{x }}} intercept: set {{{y=0}}}

{{{0=log(10-3x)}}}... log base {{{10}}} is equal to {{{zero}}} for {{{log(1)}}}=>


{{{1=10-3x}}} ...solve for {{{x}}}

{{{3x=10-1}}}

{{{3x=9}}}

{{{x=9/3}}}

{{{x=3}}} => the {{{x}}}- intercept: at ({{{3}}},{{{0}}})

the {{{y}}}- intercept:

now set {{{x=0}}} and solve for {{{y}}}

{{{y=log(10-3*0)}}}

{{{y=log(10)}}}=>{{{log(10,10)=1}}}=>

{{{y=1}}} => the {{{y}}}- intercept: at ({{{0}}},{{{1}}})


here is your link to graph:

 http://oi59.tinypic.com/2m3l6qu.jpg