Question 77979
If you have something like this:

{{{((24r^2s^2)/(3s))*((21s)/r)}}} note: I cannot see any exponents over r and s, so I'll assume they are both 2

When you divide 2 like bases with exponents, you subtract the exponents (ie {{{x^3/x^2=x^(3-2)=x^1=x}}})



{{{((8r^2s^(2-1)))*((21s)/r)}}} Divide the common bases (24/3=8) and subtract the exponents

{{{((8r^2s^1))*((21s)/r)}}} 

When you multiply common bases, you add the exponents (ie {{{x^3*x^2=x^(3+2)=x^5}}})


{{{(168r^2s^(1+1))/r}}} 


{{{(168r^2s^2)/r}}}

Now divide

{{{(168r^(2-1)s^2)}}}


{{{168r*s^2}}} So this is the simplified answer


Whenever you say {{{(2x^2+5x)/(5x)}}} you are dividing a polynomial (poly-many nomial-name) over a monomial (mono-one, nomial-name). In a sense these are monomials:

x,5x,2xy,10,etc 

Basically any terms that are alone are monomials(they have 1 term); where multiple terms that are added or subtracted are polynomials (they have many terms):

polynomials - {{{2x^2+5x+6}}}, {{{3x^2+6x+7}}},etc


I'm not sure what you mean by this "and solving fractional equations that have to have answers like x=24 or u=3"