Question 77726
						
a) this  function  describes  displacement as,  s =  Vo*t  - (1/2)*g*t^2,  showing  effect of gravity in motion of  (falling and going-up ) body.	It is in terms of initial velocity and gravity at any time.
				
see also: http://www.freewebs.com/renevencer11/-%20math/freefalling.jpg
note: copy, paste on your file & Ctrl+ click to view the link	
				
b)  after 1 sec		s =  Vo*t  - (1/2)*g*t^2				
Vo = 32 ft/sec		s  = 32*1  - (1/2)*32.2*1^2 =	15.90	ft
						
d) maximum height						
V1^2  - Vo^2  =  -2*g*h	 V1 = final velocity, equal to zero at maximum height			
h =  Vo^2/(2*g) = 15.90	ft			
						
c) it becomes a free-falling body						
s =  Vo*t  +  (1/2)*g*t^2			V0 = 0			
15.90 = (1/2)*32.2*t^2 =						
t  = sqrt(15.9 /(16.1))= 0.9938	sec