Question 921342
Find the exact value of the expression.
tan(5&#960;/6) &#8722; tan(&#960;/6)/1 + tan(5&#960;/6)tan(&#960;/6)
Identity: tan(x-y)=(tanx-tany)/(1+tanxtany) 
tan(5&#960;/6)&#8722;tan(&#960;/6)/1+tan(5&#960;/6)tan(&#960;/6)=tan(5&#960;/6-&#960;/6)=tan(4&#960;/6)=tan(2&#960;/3)