Question 921292
to graph {{{x + 3y <= 6}}} find two points that lie on a line

{{{x + 3y <= 6}}}  if {{{x=0}}}

{{{0 + 3y <= 6}}} 

{{{3y <= 6}}}

{{{y <= 6/3}}}

{{{y <= 2}}}

{{{x + 3y <= 6}}}  if {{{y=0}}}

{{{x + 3*0<= 6}}} 

{{{x +0<= 6}}}

{{{x <= 6}}}

points are: ({{{0}}},{{{2}}}) and  ({{{6}}},{{{0}}})


plot points:


{{{drawing( 600, 600, -10,10, -10, 10,circle(6,0,.2),locate(6,1,p(6,0)),circle(0,2,.2),locate(0.3,2.8,p(0,2)), graph( 600, 600, -10,10, -10, 10 )) }}}


draw a line through:x + 3y <=-x/3+ 2

{{{drawing( 600, 600, -10,10, -10, 10,circle(6,0,.2),locate(6,1,p(6,0)),circle(0,2,.2),locate(0.3,2.8,p(0,2)), graph( 600, 600, -10,10, -10, 10,-x/3+ 2 )) }}}


shade the area under line including line itself because you have &#8804 


{{{drawing( 600, 600, -10,10, -10, 10,circle(6,0,.2),locate(6,1,p(6,0)),circle(0,2,.2),locate(0.3,2.8,p(0,2)), graph( 600, 600, -10,10, -10, 10,y<=-x/3+ 2 )) }}}