Question 921225
three cards are drawn without replacement
P(3rd is Diamond) = 
P(x=1D, 3rd draw a D) =  {{{(39/52)(38/51)(13/50)}}}
+ P(x = 2D, with last a diamond) {{{(13/52)(39/51)(12/50) +(39/52)(13/51)(12/50) }}}
+ (x= 3D)  = {{{(13/52)(12/51)(11/50)}}}