Question 921014
1) 52C7 =133,784,560  , 52C11 = 60,403,728,840 , 52C13 = 635,013,559,600
2)p(forgets to turn off) = .20
p(def, turned off) = .06
p(def, left on) = .35
....
P(def..not knowing) = P(def-ON 0r def-OFF) = .80*.06 + .20*.35 = .118  0r 12 def
P(def| ON) = .35
.35*100 = 35 expected to be defective