Question 920786
{{{(5x^2 -20)/(10x^2 +10x-20)=(5(x^2-4))/(10(x^2+x-2))}}}
{{{(5x^2 -20)/(10x^2 +10x-20)=((x-2)(x+2))/(2((x+2)(x-1)))}}}
{{{(5x^2 -20)/(10x^2 +10x-20)=(x-2)/(2(x-1))}}}