Question 920664

Find two consecutive odd integers such that seven times the first is eight more than 5 times the second.

my answer ; 7x = [5(x+2)] + 8
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Good work!!

You don't need the brackets. The parentheses are enough. Thus, we have:
7x = 5(x + 2) + 8
Distribute the 5, then combine like-terms, and determine the value of x: the 1st, or 
smaller odd integer. Then add 2 to get the larger odd integer. 

You can do it!!