Question 920693

{{{y-3y^2-9}}} set it equal to zero


{{{-3y^2+y-9=0}}} ...use quadratic formula


{{{y = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} ...note that {{{a=-3}}},{{{b=1}}}, and {{{c=-9}}}


{{{y = (-1 +- sqrt( 1^2-4*(-3)*(-9) ))/(2*(-3)) }}}


{{{y = (-1 +- sqrt( 1-108 ))/(-6) }}}


{{{y = (-1 +- sqrt( -107 ))/(-6) }}}


{{{y = (-1 +- i*sqrt( 107 ))/(-6) }}}


solutions:


{{{y = -1/-6 + sqrt( 107 )i/(-6) }}}


{{{y = (1/6)(1 -sqrt( 107 )i) }}}

or


{{{y = -1/-6 - sqrt( 107 )i/(-6) }}}


{{{y = (1/6)(1 +sqrt( 107 )i) }}}