Question 920671
{{{ 200/150=(1+0.03/4)^(4t) }}} where {{{t}}}= number of years
{{{4/3=1.0075^(4t) }}}
{{{log((4/3))=4t*log((1.0075))}}}
{{{4t=log(("4/3"))/log((1.0075))}}}
{{{t=log(("4/3"))/(4*log((1.0075)))}}}
{{{t=9.62}}} (rounded)
It should take a little longer, because over 9.5 years,
That is {{{4*9.5=38}}} quarters, the $150 would grow to
{{{150*1.075^38=199.25}}} (rounded).
Then to earn the remaining $0.75, at 3% you would need {{{x}}} years,
with {{{199.25*0.03*x=0.75}}}
{{{x=0.75/(199.25*0.03)=0.13}}} (rounded),
for a total of {{{9.5+0.13=9.63}}} years.